Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_p149_p133_03
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p149 해설 - p133 마무리 15 |
| rdfs:comment | YBM 공통수학1 정답과 해설 p149의 행렬 곱셈 등식 풀이 원문. |
| math:answerText | \(-4\) |
| math:explanationText | 15 \[ AB=\begin{pmatrix}a&b\\3&-1\end{pmatrix} \begin{pmatrix}0&1\\1&0\end{pmatrix} = \begin{pmatrix}b&a\\-1&3\end{pmatrix}. \quad \text{▶ 30 \%} \] \[ BA=\begin{pmatrix}0&1\\1&0\end{pmatrix} \begin{pmatrix}a&b\\3&-1\end{pmatrix} = \begin{pmatrix}3&-1\\a&b\end{pmatrix}. \quad \text{▶ 30 \%} \] \[ \begin{pmatrix}b&a\\-1&3\end{pmatrix} = \begin{pmatrix}3&-1\\a&b\end{pmatrix} \] 에서 \(a=-1,\ b=3\)이므로 \[ a-b=-4. \quad \text{▶ 40 \%} \] |
| math:mappingConfidence | 0.92 |
| math:pageStart | 149 |
| math:problem | textbook_problem:ybm_vision_p133_03 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:matrix_equality_component_equations |
| math:usesSolutionPattern | solution_pattern:matrix_product_row_column |