YBM p138 해설 - p030 마무리 15

Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_p138_p030_01

rdf:typemath:TextbookSolution
rdfs:labelYBM p138 해설 - p030 마무리 15
rdfs:commentYBM 공통수학1 정답과 해설 p138의 서술형 풀이 원문.
math:answerText\(4ab\)
math:explanationText15 \[ (a+b+c)(a+b-c)+(a-b+c)(-a+b+c) \] \[ =\{(a+b)+c\}\{(a+b)-c\}+\{c+(a-b)\}\{c-(a-b)\}\quad \text{▶ 25 \%} \] \[ =(a+b)^2-c^2+c^2-(a-b)^2\quad \text{▶ 25 \%} \] \[ =(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab\quad \text{▶ 50 \%} \]
math:mappingConfidence0.94
math:pageStart138
math:problemtextbook_problem:ybm_vision_p030_01
math:reviewStatusreviewed
math:solutionKindworked_solution
math:usesSolutionPatternsolution_pattern:combine_like_terms_polynomial
math:usesSolutionPatternsolution_pattern:expand_with_formula