Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p127_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p127 예제 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p127 행렬의 곱셈 예제 풀이. |
| math:answerText | \(\begin{pmatrix}-10&4\\5&-12\end{pmatrix}\) |
| math:explanationText | 먼저 \(B+C=\begin{pmatrix}5&3\\0&5\end{pmatrix}\)이다. 따라서 \(AB+AC=A(B+C)=\begin{pmatrix}-2&2\\1&-3\end{pmatrix}\begin{pmatrix}5&3\\0&5\end{pmatrix}=\begin{pmatrix}-10&4\\5&-12\end{pmatrix}\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 127 |
| math:problem | textbook_problem:ybm_vision_p127_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:matrix_product_row_column |