Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p120_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p120 예제 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p120 행렬 성분 예제 풀이. |
| math:answerText | \(\begin{pmatrix}2&3\\3&4\end{pmatrix}\) |
| math:explanationText | \(a_{ij}=i+j\)이므로 \(a_{11}=2,\ a_{12}=3,\ a_{21}=3,\ a_{22}=4\)이다. 따라서 \(A=\begin{pmatrix}2&3\\3&4\end{pmatrix}\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 120 |
| math:problem | textbook_problem:ybm_vision_p120_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:matrix_entry_table_translation |