Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p069_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p069 예제 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p069 연립이차방정식 예제 풀이. |
| math:answerText | \((2,1),\ (-2,-1),\ (-\sqrt7,\sqrt7),\ (\sqrt7,-\sqrt7)\) |
| math:explanationText | \(x^2-xy-2y^2=(x-2y)(x+y)=0\)이다. \(x=2y\)이면 \(y=\pm1\), \(x=-y\)이면 \(y=\pm\sqrt7\)이므로 해는 \((2,1),(-2,-1),(-\sqrt7,\sqrt7),(\sqrt7,-\sqrt7)\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 69 |
| math:problem | textbook_problem:ybm_vision_p069_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:substitute_to_single_equation |