Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p024_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p024 예제 7 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p024 예제 7 풀이. |
| math:answerText | \((x-1)(x+4)(x-2)\) |
| math:explanationText | \(P(1)=0\)이므로 \(x-1\)이 인수이다. 조립제법으로 나누면 몫은 \(x^2+2x-8=(x+4)(x-2)\)이므로 \(P(x)=(x-1)(x+4)(x-2)\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 24 |
| math:problem | textbook_problem:ybm_vision_p024_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:remainder_theorem_substitution |
| math:usesSolutionPattern | solution_pattern:substitution_factorization |