YBM p023 예제 6 풀이

Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p023_01

rdf:typemath:TextbookSolution
rdfs:labelYBM p023 예제 6 풀이
rdfs:commentYBM 공통수학1 본문 p023 예제 6 풀이.
math:answerText⑴ \((x+1)(x-1)(x^2+4)\) ⑵ \((x^2-x+3)(x^2+x+3)\)
math:explanationText⑴ \(x^4+3x^2-4=(x^2+4)(x^2-1)=(x+1)(x-1)(x^2+4)\). ⑵ \(x^4+5x^2+9=(x^2+3)^2-x^2=(x^2-x+3)(x^2+x+3)\).
math:mappingConfidence1.0
math:pageStart23
math:problemtextbook_problem:ybm_vision_p023_01
math:reviewStatusreviewed
math:solutionKindworked_solution
math:usesSolutionPatternsolution_pattern:substitution_factorization