Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p016_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p016 예제 1 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p016 예제 1 풀이. |
| math:answerText | \(a=1,\ b=4,\ c=6\) |
| math:explanationText | \(t=x-1\)로 놓으면 \(x=t+1\)이고 \(x^2+2x+3=(t+1)^2+2(t+1)+3=t^2+4t+6\)이다. 따라서 \(a=1,\ b=4,\ c=6\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 16 |
| math:problem | textbook_problem:ybm_vision_p016_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:coefficient_comparison_substitution |