Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p011_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p011 예제 6 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p011 예제 6 풀이. |
| math:answerText | 몫: \(x^2-2x-2\), 나머지: \(-1\) |
| math:explanationText | 조립제법으로 \(x^3-3x^2+0x+1\)을 \(x-1\)로 나누면 몫은 \(x^2-2x-2\), 나머지는 \(-1\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 11 |
| math:problem | textbook_problem:ybm_vision_p011_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:synthetic_division_quotient_remainder |