Canonical URI: https://w3id.org/kmath/textbook_solution/ybm_solution_body_p008_03
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | YBM p008 예제 4 풀이 |
| rdfs:comment | YBM 공통수학1 본문 p008 예제 4 풀이. |
| math:answerText | \(a^2+b^2+c^2+2ab+2bc+2ca\) |
| math:explanationText | 세 항의 제곱 공식을 이용하면 \((a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 8 |
| math:problem | textbook_problem:ybm_vision_p008_03 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:expand_with_formula |