Canonical URI: https://w3id.org/kmath/textbook_solution/visang_solution_p159_workbook_p141_12
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 비상 p141 수학 익힘책 IV-12 풀이 |
| rdfs:comment | 비상 공통수학1 정답 및 해설 p159의 수학 익힘책 p141 IV-12 풀이. |
| math:answerText | \[ \begin{pmatrix}5&9\\-3&-4\end{pmatrix} \] |
| math:explanationText | \[ A^2=\begin{pmatrix}-2&-3\\1&1\end{pmatrix},\quad A^3=E \] 이므로 \[ 2A^5-4A^2+A=-2A^2+A = \begin{pmatrix}5&9\\-3&-4\end{pmatrix} \] |
| math:mappingConfidence | 1.0 |
| math:pageStart | 159 |
| math:problem | textbook_problem:visang_workbook_p141_12 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:identity_matrix_product_property |
| math:usesSolutionPattern | solution_pattern:matrix_product_row_column |