Canonical URI: https://w3id.org/kmath/textbook_solution/visang_solution_p142_p016_02
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 비상 p016 문제 10 풀이 |
| rdfs:comment | 비상 공통수학1 정답 및 해설 p142의 p016 문제 10 풀이. |
| math:answerText | (1) \(Q=2x^2-x+4,\ R=-3\) (2) \(Q=3x-5,\ R=2x+6\) |
| math:explanationText | (1) \(2x^3+x^2+3x+1=(x+1)(2x^2-x+4)-3\) (2) \(3x^3-2x^2+1=(x^2+x+1)(3x-5)+2x+6\) |
| math:mappingConfidence | 1.0 |
| math:pageStart | 142 |
| math:problem | textbook_problem:visang_vision_p016_02 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:synthetic_division_quotient_remainder |