Canonical URI: https://w3id.org/kmath/textbook_solution/visang_solution_body_p015_03
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 비상 p015 예제 3 풀이 |
| rdfs:comment | 비상 공통수학1 본문 p015 예제 3 풀이. |
| math:answerText | \(18\) |
| math:explanationText | \((x+y)^3=x^3+3x^2y+3xy^2+y^3\)에서 \(x^3+y^3=(x+y)^3-3x^2y-3xy^2=(x+y)^3-3xy(x+y)=3^3-3\times1\times3=18\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 15 |
| math:problem | textbook_problem:visang_vision_p015_03 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:expand_with_formula |