미래엔 p058 예제 2 풀이

Canonical URI: https://w3id.org/kmath/textbook_solution/mirae_solution_body_p058_01

rdf:typemath:TextbookSolution
rdfs:label미래엔 p058 예제 2 풀이
rdfs:comment미래엔 공통수학1 교과서 p058 본문 예제 2 풀이.
math:answerText\((x-3-i)(x-3+i)\)
math:explanationText이차방정식 \(x^2-6x+10=0\)의 근이 \(x=3\pm i\)이므로 \[ x^2-6x+10=\{x-(3+i)\}\{x-(3-i)\} =(x-3-i)(x-3+i). \]
math:mappingConfidence1.0
math:pageStart58
math:problemtextbook_problem:mirae_vision_p058_01
math:reviewStatusreviewed
math:solutionKindworked_solution
math:usesSolutionPatternsolution_pattern:complex_number_algebra
math:usesSolutionPatternsolution_pattern:roots_coefficients_symmetric_expression