Canonical URI: https://w3id.org/kmath/textbook_solution/jihak_solution_body_p031_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 지학사 p031 예제 3 풀이 |
| rdfs:comment | 지학사 공통수학1 본문 p031 예제 3 풀이. |
| math:answerText | (1) \((x^2+1)(x+2)(x-2)\) (2) \((x+y+3)^2\) |
| math:explanationText | (1) \(x^2=X\)로 놓으면 \(x^4-3x^2-4=X^2-3X-4=(X+1)(X-4)=(x^2+1)(x^2-4)=(x^2+1)(x+2)(x-2)\)이다. (2) \(x+y=X\)로 놓으면 \((x+y)(x+y+6)+9=X(X+6)+9=X^2+6X+9=(X+3)^2=(x+y+3)^2\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 31 |
| math:problem | textbook_problem:jihak_vision_p031_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:substitution_factorization |