Canonical URI: https://w3id.org/kmath/textbook_solution/donga_solution_p147_p044_06
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 동아 p044 스스로 해결하기 6 풀이 |
| rdfs:comment | 동아 공통수학1 정답 및 풀이 p147의 p044 스스로 해결하기 6 풀이. |
| math:answerText | \(1-\frac{1}{3}i\) |
| math:explanationText | \[ \frac{1}{Z}=\frac{1}{Z_1}+\frac{1}{Z_2} =\frac{1}{1-i}+\frac{1}{2+i} =\frac{1+i}{2}+\frac{2-i}{5} =\frac{9+3i}{10} \] 이므로 \[ Z=\frac{10}{9+3i} =\frac{10(9-3i)}{(9+3i)(9-3i)} =1-\frac{1}{3}i. \] |
| math:mappingConfidence | 1.0 |
| math:pageStart | 147 |
| math:problem | textbook_problem:donga_vision_p044_06 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:complex_number_algebra |
| math:usesSolutionPattern | solution_pattern:conjugate_complex_rationalization |