동아 p050 예제 1 풀이

Canonical URI: https://w3id.org/kmath/textbook_solution/donga_solution_body_p050_example_01

rdf:typemath:TextbookSolution
rdfs:label동아 p050 예제 1 풀이
rdfs:comment동아 공통수학1 본문 p050의 예제 1 풀이.
math:answerText(1) \(-\frac{7}{4}\) (2) \(\frac{3}{4}\)
math:explanationText이차방정식의 근과 계수의 관계에 의하여 \(\alpha+\beta=\frac{3}{2},\ \alpha\beta=2\)이다. (1) \[ \alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta =\left(\frac{3}{2}\right)^2-2\times2=-\frac{7}{4} \] (2) \[ \frac{1}{\alpha}+\frac{1}{\beta} =\frac{\alpha+\beta}{\alpha\beta} =\frac{3}{2}\div2=\frac{3}{4}. \]
math:mappingConfidence1.0
math:pageStart50
math:problemtextbook_problem:donga_vision_p050_example_01
math:reviewStatusreviewed
math:solutionKindworked_solution
math:usesSolutionPatternsolution_pattern:roots_coefficients_symmetric_expression