Canonical URI: https://w3id.org/kmath/textbook_solution/donga_solution_body_p042_check_division
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 동아 p042 확인하기 1 풀이 |
| rdfs:comment | 동아 공통수학1 본문 p042의 복소수 나눗셈 확인하기 풀이. |
| math:answerText | \(\frac{1}{2}+\frac{3}{2}i\) |
| math:explanationText | \[ \frac{2+i}{1-i} =\frac{(2+i)(1+i)}{(1-i)(1+i)} =\frac{2+2i+i+i^2}{1-i^2} =\frac{(2-1)+(2+1)i}{1-(-1)} =\frac{1}{2}+\frac{3}{2}i \] |
| math:mappingConfidence | 1.0 |
| math:pageStart | 42 |
| math:problem | textbook_problem:donga_vision_p042_check_division |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:complex_number_algebra |
| math:usesSolutionPattern | solution_pattern:conjugate_complex_rationalization |