Canonical URI: https://w3id.org/kmath/textbook_solution/donga_solution_body_p028_01
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 동아 p028 예제 1 풀이 |
| rdfs:comment | 동아 공통수학1 p028 본문 예제 1의 인수분해 풀이. |
| math:answerText | (1) \((x+2)^3\) (2) \((2x+y)(4x^2-2xy+y^2)\) |
| math:explanationText | (1) \[ x^3+6x^2+12x+8=x^3+3\cdot x^2\cdot2+3\cdot x\cdot2^2+2^3=(x+2)^3 \] (2) \[ 8x^3+y^3=(2x)^3+y^3=(2x+y)\{(2x)^2-2xy+y^2\} \] 따라서 \((2x+y)(4x^2-2xy+y^2)\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 28 |
| math:problem | textbook_problem:donga_vision_p028_01 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:substitution_factorization |