Canonical URI: https://w3id.org/kmath/textbook_solution/chunjae_jeon_solution_p159_p137_review_07_identity_linear_combination
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 천재전 p159 정답 - p137 중단원 확인하기 07 |
| rdfs:comment | 천재전 공통수학1 정답과 해설 p159의 p137 중단원 확인하기 07번 풀이 원문. |
| math:answerText | \[ \begin{pmatrix}-2&-6\\9&-13\end{pmatrix} \] |
| math:explanationText | \[ A=\begin{pmatrix}3&-2\\1&0\end{pmatrix} - \begin{pmatrix}3&0\\0&3\end{pmatrix} = \begin{pmatrix}0&-2\\1&-3\end{pmatrix} \] \[ B=A-\begin{pmatrix}1&0\\-3&2\end{pmatrix} = \begin{pmatrix}0&-2\\1&-3\end{pmatrix} - \begin{pmatrix}1&0\\-3&2\end{pmatrix} = \begin{pmatrix}-1&-2\\4&-5\end{pmatrix} \] 따라서 \[ A+2B=\begin{pmatrix}-2&-6\\9&-13\end{pmatrix} \] |
| math:mappingConfidence | 1.0 |
| math:pageStart | 159 |
| math:problem | textbook_problem:chunjae_jeon_vision_p137_review_07_identity_linear_combination |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:identity_matrix_product_property |
| math:usesSolutionPattern | solution_pattern:matrix_linear_combination_entries |