Canonical URI: https://w3id.org/kmath/textbook_solution/chunjae_jeon_solution_body_p033_02
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 천재전 p033 예제 2 풀이 |
| rdfs:comment | 천재전 공통수학1 본문 p033의 예제 2 풀이. |
| math:answerText | \((x-1)(x+4)(x^2+3x+3)\) |
| math:explanationText | \(x^2+3x=X\)로 놓으면 \[ (x^2+3x)(x^2+3x-1)-12=X(X-1)-12=X^2-X-12 \] \[ =(X-4)(X+3)=(x^2+3x-4)(x^2+3x+3) \] \[ =(x-1)(x+4)(x^2+3x+3) \] 이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 33 |
| math:problem | textbook_problem:chunjae_jeon_vision_p033_02 |
| math:reviewStatus | reviewed |
| math:solutionKind | worked_solution |
| math:usesSolutionPattern | solution_pattern:substitution_factorization |