Canonical URI: https://w3id.org/kmath/textbook_solution/chunjae_hong_solution_p156_p139_final_review_05
| rdf:type | math:TextbookSolution |
|---|---|
| rdfs:label | 천재홍 p139 대단원 평가하기 5 풀이 |
| rdfs:comment | 천재홍 공통수학1 정답 및 풀이 p156의 p139 대단원 평가하기 5 풀이. |
| math:answerText | \(x=-6,\ y=-1\) |
| math:explanationText | \[ AB=\begin{pmatrix}1&2\\3&6\end{pmatrix} \begin{pmatrix}x&2\\3&y\end{pmatrix} = \begin{pmatrix}x+6&2+2y\\3x+18&6+6y\end{pmatrix}. \] \(AB=O\)이므로 \(x+6=0,\ 2+2y=0\)에서 \(x=-6,\ y=-1\)이다. |
| math:mappingConfidence | 1.0 |
| math:pageStart | 156 |
| math:problem | textbook_problem:chunjae_hong_vision_p139_final_review_05 |
| math:reviewStatus | reviewed |
| math:solutionKind | answer_only |
| math:usesSolutionPattern | solution_pattern:matrix_equality_component_equations |
| math:usesSolutionPattern | solution_pattern:matrix_product_row_column |