천재홍 p134 예제 1 풀이

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rdf:typemath:TextbookSolution
rdfs:label천재홍 p134 예제 1 풀이
rdfs:comment천재홍 공통수학1 교과서 p134 본문에서 이미지 판독으로 추출한 예제 1 풀이.
math:answerText(1) \((14)\) (2) \(\begin{pmatrix}4&5\\-2&1\end{pmatrix}\)
math:explanationText(1) \[ \begin{pmatrix}1&3\end{pmatrix}\begin{pmatrix}2\\4\end{pmatrix} =(1\times2+3\times4)=(14) \] (2) \[ \begin{pmatrix}1&2\\-1&0\end{pmatrix} \begin{pmatrix}2&-1\\1&3\end{pmatrix} = \begin{pmatrix} 1\times2+2\times1 & 1\times(-1)+2\times3\\ (-1)\times2+0\times1 & (-1)\times(-1)+0\times3 \end{pmatrix} = \begin{pmatrix}4&5\\-2&1\end{pmatrix}. \]
math:mappingConfidence1.0
math:pageStart134
math:problemtextbook_problem:chunjae_hong_vision_p134_example_01
math:reviewStatusreviewed
math:solutionKindworked_solution
math:usesSolutionPatternsolution_pattern:matrix_product_row_column